Practise the method.Example 1For y=−(x−(0))2+(1), find the turning point.yy = −(x − (0))² + (1). Horizontal axis: x; vertical axis: y. Horizontal range -5 to 5; vertical range -10 to 12.-5-2.502.55-10010xy=−(x−(0))2+(1)Show worked answerAnswer: (0,1)Vertex form y=a(x−h)2+k has turning point (h,k), so it is (0,1).Example 2The graph is y=(x−(1))2+(−2). Its axis of symmetry is x=s. Find s.yy = (x − (1))² + (-2). Horizontal axis: x; vertical axis: y. Horizontal range -5 to 5; vertical range -10 to 12.-5-2.502.55-10010xy=(x−(1))2+(−2)Show worked answerAnswer: 1Equal horizontal offsets from x=1 give equal squared terms. The axis is x=1.Example 3For y=−(x−(1))2+(−3), find y when x=3.yy = −(x − (1))² + (-3). Horizontal axis: x; vertical axis: y. Horizontal range -5 to 5; vertical range -10 to 12.-5-2.502.55-10010xy=−(x−(1))2+(−3)Show worked answerAnswer: −7Substitute x=3:y=−(2)2+(−3)=−7.