Practise the method.Example 1In triangle ABC, DE ∥ BC with D on AB and E on AC. ∠BAC=60∘ and ∠ADE=40∘. Find ∠ACB=x, in degrees.Triangle with a parallel segmentTriangle with a parallel segmentDE is parallel to BC. The angle at A is 60 degrees and ADE is 40 degrees. The angle at C is x. Diagram not to scale. Use the labelled measurements.ABCDE60°40°x°Diagram not to scaleShow worked answerAnswer: 80Parallel lines give ∠ABC= ∠ADE=40∘.Triangle angles sum to 180∘x=180−60−40=80∘.Example 2ABCD is a parallelogram. Its diagonal AC splits angle A into ∠BAC=20∘ and ∠CAD=x∘. Angle ABC is (2x+70)∘. Find angle CDA=y, in degrees.Parallelogram with a diagonalParallelogram with a diagonalABCD is a parallelogram with diagonal AC. BAC is 20 degrees, CAD is x degrees and ABC is (2x + 70) degrees. Angle CDA is y. Diagram not to scale. Use the labelled measurements.ABCD20°x°(2x + 70)°y°Diagram not to scaleShow worked answerAnswer: 130Adjacent angles A and B sum to 180∘:(20+x)+(2x+70)=180.Thus x=30∘.Opposite angles B and D are equaly=2×30+70=130∘.Example 3In triangle ABC, DE ∥ BC with D on AB and E on AC. ∠BAC=40∘ and ∠ADE=45∘. Find ∠ACB=x, in degrees.Triangle with a parallel segmentTriangle with a parallel segmentDE is parallel to BC. The angle at A is 40 degrees and ADE is 45 degrees. The angle at C is x. Diagram not to scale. Use the labelled measurements.ABCDE40°45°x°Diagram not to scaleShow worked answerAnswer: 95Parallel lines give ∠ABC= ∠ADE=45∘.Triangle angles sum to 180∘x=180−40−45=95∘.